how do i do this problem?

Question

2x^2-98

Answer 1

2x^2-98 = 0
divide by 2: x^2-49=0
isolate x: x^2=49
take the sqrt of both sides: x=+/- 7

Answer 2

2x^2-98 is a quadratic equation so it'll have 2 roots
Equating to 0:

2x^2-98=0
=> 2(x^2-49)=0
=> (x-7)(x+7)=0
=> x= 7 or x=-7




the roots are x=7 and x=-7

Answer 3

When doing this question you must first move the -98 to the opposite side, then divide that by 2, then square root that answer, and x will be all alone. it would look like this:
2x^2-98
98=2x^2
49=x^2
7=x

Answer 4

2x^2-98

2(x-49)

2(x+7) (x-7)

Factor the problem. Your greatest common factor is 2. Remaining is 2(x-49). however it's still factorable so factor (x-49).
It will be (x+7) (x-7). Final answer 2 (x+7) (x-7)