factoring polynomials?
16-49n^2
How do I factor this since there isnt a common number that goes into both 49 and 16?
I dont understand this, could someone explain how to do it to me?
2007-03-02 10:13:13 · 3 answers · asked by Anonymous in Education & Reference ➔ Other - Education
This is called the difference of two squares, since 16 is 4 squared and 49n^2 is (7n) squared, and they are subtracted. You factor them by FOIL like this:
(4+7n)(4 - 7n)
2007-03-02 10:24:43 · answer #1 · answered by hayharbr 7 · 0⤊ 0⤋
If it didn't get through
This is a difference of squares problem in the form of A squared minus B squared Which is equal to (A + B) times (A - B),
Here A is 4 and B is 7n.
2007-03-02 10:19:03 · answer #2 · answered by a simple man 6 · 0⤊ 0⤋
the respond is (4-7n)(4+7n) look what occurs once you multiply making use of the FOIL approach (First, exterior, interior, final) you get: sixteen + 28n - 28n -49n^2 once you combine the words, the beneficial and negitive "28n"'s cancel one yet another out. this way of factoring is named something like "sq. factoring" because of the fact the "sixteen" and the "40 9" are the sq. roots of four and seven.
2016-10-17 03:23:47 · answer #3 · answered by ? 4 · 0⤊ 0⤋