factoring polynomials?
16-49n^2
How do I factor this since there isnt a common number that goes into both 49 and 16?
I dont understand can someone explain this process on how to do this to me?
2007-03-02 10:07:45 · 4 answers · asked by Anonymous in Education & Reference ➔ Other - Education
If there is seemingly no common factor, then it is 1 because 1 is a factor of all numbers,
Ps do you go to north middle
2007-03-02 10:13:55 · answer #1 · answered by arch_gamer17 1 · 0⤊ 1⤋
Alright, it's been years, but I'll give it a go:
I think it would be (4 - 7n)(4 + 7n)
Multiplied out, it would be: 16 + 28n - 28n - 49n^2
Or simply: 16 - 49n^2
In this case, the common element is that you can get the root of 16, 49, and n^2, which is 4, 7, and n respectively.
2007-03-02 10:16:11 · answer #2 · answered by Anonymous · 0⤊ 0⤋
take the square root of 16 and -49n^2
so now the problem will look like this: 4-7n
now u bring the 4 over to the other side: -7n=-4
then divide -7 by both sides: n=4/7
thats ur answer
hope i helped
2007-03-02 10:13:37 · answer #3 · answered by Anonymous · 0⤊ 1⤋
(4-7n^2)(4+7n^2) The clue to this type of question is that both numbers are square numbers. This only works if the original question has a minus sign.
2007-03-02 10:13:59 · answer #4 · answered by Dusie 6 · 0⤊ 0⤋