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hexagon...or with any body with n sides???

2007-03-01 21:55:13 · 8 answers · asked by anshuman p 2 in Science & Mathematics Engineering

8 answers

Has to be more than 8...ahhhemmm.!

2007-03-01 22:02:36 · answer #1 · answered by Anonymous · 0 0

If you mean within the perimeter of a regular polygon then a polygon with 'n' sides will always have 'n' equilateral triangles within the perimeter. So, an Octagon would have 8. If you are thinking about how many can exist if you do not use the inscribing circles center as a common point for vertices then there would be many more, 3'n'.

2007-03-02 06:03:47 · answer #2 · answered by Nightstalker1967 4 · 0 0

Any number................. because it depends on the size of the shape ex. a small octagon can have 20 triangles and a big octagon can have 100 triangles

2007-03-02 06:08:27 · answer #3 · answered by Mikey 2 · 0 0

n-2...
triangle forms 1 (3 sides - 2)
square forms 2 (4 sides - 2)
etc..

from a mathematical perspective, infinitely many. just make triangles within the triangles

2007-03-02 05:58:34 · answer #4 · answered by alimoalem2000 2 · 0 0

infinite. It can be certain only by specifying what kind of triangle you want to form (equilateral, right, isosceles,scalene).

2007-03-02 09:20:15 · answer #5 · answered by cathy374507 1 · 1 0

use Combination:

C(n,r) = n!/[(n-r)!r!]

=8!/(5!)(3!)

=(8)(7)(6)(5!)/(5!)(3!)

=56

2007-03-02 06:08:18 · answer #6 · answered by datz 2 · 0 0

what are your rules for forming them?

2007-03-02 05:58:05 · answer #7 · answered by Anonymous · 0 0

i think its 56.

2007-03-02 08:13:58 · answer #8 · answered by pinoy henyo 1 · 0 0

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