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6 answers

If the subs are 2 ohm DVC, you can wire it like so for a 3 ohm load http://i81.photobucket.com/albums/j230/sparky3489/TRI-DVC-PARSER.jpg

2007-03-01 12:42:12 · answer #1 · answered by Anonymous · 0 0

As far a wiring your subs, it depends on the impedance load each woofer is. If you have 2 ohm dvc you will have to do a 1.33 load, if they are 4 ohm dvc you will have a 2.67 load. Either way should work depending if your amp can handle a 1.33 load or not. The type of enclosure you use is going to have a lot with the output of your woofers too. If you have the room, you should do a vented box. Thats were you are going to get your max output from those woofers. For box specs go to www.kicker.com

2007-03-01 12:55:57 · answer #2 · answered by Woody 4 · 0 0

If there 4 Ohmers, and the amp delivers it's max power into 2 Ohms, then paralleling all 3 would make the amp kick like crazy, but you would have to watch the volume, as you would be over driving your amp.

2007-03-01 12:39:58 · answer #3 · answered by 1000 Man Embassy 5 · 0 0

It depends if your amp is stable at 1 or 2 ohms if so then wire them so one + wire from the amp goes to the + on the first speaker from the first speaker connect a wire from the - to the + on the second speaker from the second speaker hook up the - to the + on the third speaker from the third speaker run the wire from the - to the - on the amp. simmer for 12 minutes, stir, and enjoy! make sure you fuse the power to your amp or you'll smoke it.

2007-03-01 12:46:39 · answer #4 · answered by bmtroubleu325es 1 · 0 1

stay removed from MTX they're absolute junk, bypass with the kicker comps or much greater useful 2 12" L5 solobarics. you will get them for roughly $3 hundred a pair on Ebay. Thats the place I have been given mine and it grow to be the besr selection I made.

2016-11-26 23:10:13 · answer #5 · answered by ? 4 · 0 0

its two things you would have to do:
you would have to do a cross over..........
and get some ear plugs!

2007-03-01 12:41:17 · answer #6 · answered by The King 6 · 0 0

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