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heres the design
http://img137.imageshack.us/img137/9183/save0299za0.jpg
if not then tell me why it doesn't work

2007-03-01 11:06:42 · 6 answers · asked by macgyver 1 in Science & Mathematics Engineering

heres a more detailed picture of it
http://img292.imageshack.us/img292/7672/save0300hh0.jpg

2007-03-01 11:29:01 · update #1

6 answers

Not probably won't oscillate, it won't oscillate at all. The capacitors are improperly connected. You do need the capacitors for feedback, but you also need a DC path to bias the Base of each of the transistors. What you are trying to accomplish is a basic DC to AC inverter. You can find a similar design, but one that will work, in the 1976 issue of the AREL Amateur Radio Handbook. This inverter, when operating, will produce a square wave type output running at about 60 Hz. Don't try to run any TVs or other sound type devices with it. The buzz that it will produce if you try will be quite annoying.
The battery, by the way, is in the wrong place. The Positive side needs to connect to the center tap of the transformer, the negative to the common point of the transistor emitters. Connect one capacitor from the the collector side of T1 to the base of T2, from the collector side of T2 to the base of T1. Connect 1 resistor, try 470 ohms first, (this may take a little experimenting) from the base of T1 to the emitter of that transistor, and a similar resistor connected the same way to T2. What you are building, besides a DC/AC inverter, is a free running flip-flop (or multivibrator) that has a power transformer as it's load.

2007-03-01 16:26:26 · answer #1 · answered by Anonymous · 0 0

shifting coil in a generator produce ac voltage and modern linked to transformers to step up voltage. Generator run via best mover like turbine. AC could be switched over into dc via rectifier or commutator.

2016-12-14 08:29:57 · answer #2 · answered by scheiber 4 · 0 0

it probably won't oscillate.

to make an oscillator you need to feedback some of the output signal to the input in the correct phase to make the circuit have positive feedback. In the circuit you show, the transistors will be biased off, and there does not appear to be any feedback.

checkout colpitts, clapp, armstrong and hartley oscillators

2007-03-01 11:52:15 · answer #3 · answered by elentophanes 4 · 0 0

not sure, it looks like it SHOULD, but it would depend on you output sorce ( by that i mean are you making the energy from burning, static, charge. . . etc. OR are you just drawing it from an outlet )

hope it makes sense, it really depends on what alternator source you have, or what MAKES it alternate or AC. the drawing just isnt detailed enough... sorry

2007-03-01 11:14:49 · answer #4 · answered by fmjaguar7 2 · 0 0

No. The dioes are cut-off

2007-03-01 11:24:34 · answer #5 · answered by JAMES 1 · 0 0

yes it will because the output is not rectified!

2007-03-01 11:25:51 · answer #6 · answered by JGuyot20 1 · 0 1

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