i am working on a diffrential amplifier but i cannot quite understand what slew rate is and how it affects the output. thanks in advance.
2007-02-28 22:00:29 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
Slew rate of an opamp is its max voltage changing rate vs. time. The output stage has internal and, in your case, external capacitive loads. As the input voltage steps up (or down) the output cannot follow that sharp-square step instantly because the load capacitors take time to charge (and discharge).
A sine wave input becomes a triagular wave output because certain segments of the sine curve have the rate of voltage change with time, that is the first derivative with time, larger than the slew rate (for the specific capacitive load).
2007-02-28 22:30:24 · answer #1 · answered by sciquest 4 · 0⤊ 0⤋
'Slew rate' is the rate of change of voltage with respect ot time (mathematically it's dV/dt or the 'slope' of the waveform as seen on an oscilloscope).
If you're getting a triangular output with a large capacitive load, it probably means that your 'amplifier' is so badly loaded that all it can do is act as a (limited) current source to charge/discharge the capacitor.
HTH âº
Doug
2007-02-28 22:09:42 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
what is it you are trying to build?
2007-02-28 22:07:36 · answer #3 · answered by Burnt Emberes 3 · 0⤊ 0⤋