Enginieering and math question!!!! help!!!?
A commonly used rule of thumb is that the average velocity in a pipe should be about 1 m/s or less for "thin" fluids(viscosity about water). If a pipe needs to deliver 6,000 m^3 of water per day, what diameter is required to sastify the 1 m/s rule?
2007-02-28 15:36:54 · 4 answers · asked by el tuani 1 in Science & Mathematics ➔ Engineering
6000 m^3 / day = 0.07 m^3/sec
Area = pi r^2 m^2
Volumetric Flow / Area = linear speed
linear speed = 1 m/s
0.07 / pi r^2 = 1
pi r^2 = 0.07
r^2 = 0.07/pi = 0.022
r = 0.149 m
Maximum pipe size is 29.8 cm diameter** haven't checked the math, but the logic is correct** and it sounds about right.
2007-02-28 15:55:41 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Possum's got the right method, but where she says "maximum diameter" it should read "minimum diameter".
The question is saying that flow should NOT EXCEED 1m/s
It's got nothing to do with pressure etc.
2007-03-02 19:00:14 · answer #2 · answered by Valmiki 4 · 0⤊ 0⤋
ABOUT 0.297 METERS IN DIA
VOL FLOW RATE = ID AREA *VELOCITY
BREAKDOWN THE UNITS BASED ON A VEL OF 1 M/S ...
2007-02-28 23:53:57 · answer #3 · answered by dugal45 3 · 0⤊ 0⤋
0.2973m
2007-02-28 23:49:16 · answer #4 · answered by mommyme 2 · 0⤊ 0⤋