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For a liquid-liquid ternary phase diagram, if a point lies between two tie lines, how do we interpolate between the two tie lines to get the required amount of each of the 2 phases in equilibrium?

2007-02-27 19:11:02 · 3 answers · asked by sky_blue 1 in Science & Mathematics Engineering

3 answers

Sciquest may have a valid point, but I don't understand it.

So, you've got a point that doesn't fall on a tie line. Not a surpise, since there are a large number of such points....an infinite number. Two easy strategies:

1. Visually interpolate the tie lines. Simply predict new tie lines from the visual trend that you see in the tie lines on the ternary phase diagram.

2. Replot the tie line data in a format that you can
easily interpolate from a smooth curve. For example, plot x_I vs. x_II and y_I vs y_II for each
tie line. I think you'll see an example of this process in some texts. If not, look at Perry's.

2007-02-28 09:01:39 · answer #1 · answered by farmer 4 · 0 0

Tie Lines Ternary Phase Diagram

2016-12-12 09:35:28 · answer #2 · answered by lucy 4 · 0 0

Do not care about tie lines and the lever rule: they are only relevant for binary phase diagrams. On a ternary diagram, simply draw three lines paralleling the three sides of the boundary triangle and read the compositions directly at the points the drawn lines cut the sides of the triagle.

2007-02-27 20:00:09 · answer #3 · answered by sciquest 4 · 0 0

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