2007-02-27 08:51:52 · 8 answers · asked by CHAR R 1 in Education & Reference ➔ Other - Education
Since you said you are throwing dice(2), not die(1)
if both dice are thrown. then the odds are 54.54% to roll a even number. 6\11
45.45% to throw odd 5\11
2,4,6,8,10,12 -- even -6
3,5,7,9,11 -- odd -5
2007-02-27 09:03:41 · answer #1 · answered by GlooBoy 3 · 0⤊ 0⤋
First role = 1/2 (of the numbers on the die, half are even)
Second role = 1/2 (the first roll does not affect the second)
The odds of getting even numbers for 2 consecutive rolls, however, is 1/2 times 1/2 = 1/4. (.5 * .5 = .25)
The odds of getting even numbers for 3 consecutive rolls is 1/2 times 1/2 times 1/2 = 1/8 (.5 * .5 *.5 = .125)
2007-02-27 08:57:53 · answer #2 · answered by jbtascam 5 · 1⤊ 0⤋
1/2
2007-02-27 08:59:36 · answer #3 · answered by bowwifey 1 · 0⤊ 0⤋
Should be 1/6.
2007-02-27 08:56:07 · answer #4 · answered by Anonymous · 0⤊ 1⤋
3 of the six numbers are even, right? So that's half. You have a 50% chance. It doesn't matter that you roll it twice. This answer is just a simplified version.
2007-02-27 08:57:28 · answer #5 · answered by amanda c 1 · 0⤊ 0⤋
1:2
The odds don't change no matter how many times you roll. Each roll has the same 1:2 odds.
2007-02-27 08:56:47 · answer #6 · answered by Anonymous · 0⤊ 0⤋
If you count 2 then daaa 1/2
2007-02-27 08:55:56 · answer #7 · answered by honor roller 2 · 0⤊ 0⤋
2/4 / 1/2 / 3/6 get it it is HALF.
2007-02-27 08:56:27 · answer #8 · answered by Anonymous · 0⤊ 0⤋