The 2.4kg particle moves in the horizontal x-y plane and has the velocity shown at time t=0. If the force F=2+(3t^2)/4 newtons, where t is time in seconds, is applied to the particle in the y-direction beginning at time t=0, determine the velocity v of the particle 4 seconds after F is applied and specify the corresponding angle θ measured counterclockwise fromt he x-axis to the direction fo the velocity.
The picture has a 2.4kg circle and a force F going up which is on the y x-axis and a velocity going down it has a positve x and a negative y and a 3/4 angle.
2007-02-26
16:42:16
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1 answers
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asked by
Anonymous
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Science & Mathematics
➔ Engineering