I have two very difficult physics electricity circuit questions that i have been trying to do for the past few hours. Can someone please try them and show your work so i can understand what you did to solve the questions.
R stands for Resistance!
V stands for Voltage!
I stands for Current!
The "Re" is the sum of all the resistance in the circuit.
They are posted on this webpage:
http://piczo.com/mohamadatwy?cr=1&rfm=y
2007-02-26 10:19:48 · 5 answers · asked by many men 1 in Science & Mathematics ➔ Engineering
You need to make equivalent resistors so that you can colapse the circuit and solve the problem.
I will do the first one. You get to do the second one.
R3 + R4 = 20 Ohms
20 Ohms || R2 = 4 Ohms (note || means in parallel)
4 Ohms + R1 + R5 = 15 Ohms
So now we know that to total current coming out of the battery is
V/15 = 30/15 = 2Amps , this is also the current flowing through R1 and R5. The voltage across each of these two resistors can be firgured out by using the 2Amps and V = IR
Now we need the voltage across the combination of R2, R3 and R4. We previously figured the combined resistance to be 4 Ohms So the voltage across R2 is 4 Ohms * 2 Amps = 8 Volts, the current through R2 is 8 Volts / 5 Ohms = 1.6 Amps this leaves 2 Amps - 1.6 Amps = 0.4 Amps for R3 and R4. So the voltage across R3 is .4 amps * 12 Ohms = 4.8Volts and across R4 = .4 Amps * 8 Ohms = 3.2 Volts. Note that the voltage across R3 and R4 adds up to 8 Volts just like it should.
This information should give all the answers for the first problem, ie currents and voltages across all resistors.
The same procedure will solve the second problem.
2007-02-26 10:37:36 · answer #1 · answered by rscanner 6 · 0⤊ 0⤋
The resistors R2 R3 and R4 have an equlivent reistance of 4.29 ohms.
Re therefore is 15.29 ohms, Io is 1.96 Amps. This should get you started
2007-02-26 20:52:16 · answer #2 · answered by John S 6 · 0⤊ 0⤋
Leg a = R1 +R2 +R5
leg b=R1 +R3 =R4 +R5 This is the series legs.
The parell 1 over leg a + 1over leg B after u add the reciprocals do the reciprocal of the answer.
2007-02-26 18:55:55 · answer #3 · answered by JOHNNIE B 7 · 0⤊ 0⤋
Do you know the difference between series and parallel?
Maybe you can tell us which ones you think are in series and which ones are in parallel?
Start with Parallel resistors. Find their series value, then replace the 2 parallel resistors with the series one that you found the value for.
Keep doing that.
2007-02-26 18:32:07 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I think batteries
2007-02-26 18:24:14 · answer #5 · answered by jajajajammmmmmmmmm 1 · 0⤊ 3⤋