I am moving in to an apartment that has 85 sq. ft for a den I am trying to figure out the length and the width of the room.
2007-02-25 15:17:18 · 5 answers · asked by MsItSeams 2 in Education & Reference ➔ Other - Education
Well, square footage is determined by L x W. So, given just the sq. ft. does not help much. Here is a list of possible sq. ft.:
14 x 6
12 x 7
10 x 8.5
9 x 9.5
Maybe that will help.
2007-02-25 15:23:43 · answer #1 · answered by livinlard 1 · 0⤊ 0⤋
merely set up 2 equations and sparkling up W x L = 35 & 2W + 2L = 27 L = (35/W) 2W + 2(35/W) = 27 2W + 70/W = 27 2W^2 + 70 = 27W 2W^2 - 27W + 70 = 0 after which component... you get (W - 3.5)(W - 10) the two certainly one of which fulfill the equation, so of course the width is the smaller one and the size, the better. W = 3.5 L = 10
2016-12-18 11:00:57 · answer #2 · answered by ? 3 · 0⤊ 0⤋
Well, it could have multiple lengths and widths. It could be a little bigger than 9' x 9', or it could be a little less than 11' x 7.75', or it could be around 10.5' x 8'. You just have to find the floorplan of the house to see the dimensions.
2007-02-25 15:21:29 · answer #3 · answered by Mark D 2 · 0⤊ 0⤋
9.22 X 9.22 Ft it is a square or if rectangular it can be 8.5 X 10 Ft.
Area = Lenght multiplied by Width
2007-02-25 15:24:56 · answer #4 · answered by exo 7 · 0⤊ 0⤋
there is many answers to this answer. it oculd be 1 by 85(hihgly dout ti but you know what i mean) but ill be realistic. the most reasonable answer is around 9.25 by 9.25
2007-02-25 15:23:19 · answer #5 · answered by djmistaspot 3 · 0⤊ 0⤋