2007-02-24 23:19:17 · 4 answers · asked by rolaine 1 in Science & Mathematics ➔ Mathematics
Let the integers be x and x + 2
The required linear equation would be:
2(x + 2) = 3x - 40
2x + 4 = 3x - 40
2x = 3x - 40 -4
2x = 3x - 44
2x - 3x = -44
-x = -44
x = 44
x + 2 = 46
The required integers are 44 and 46
2007-02-25 00:33:46 · answer #1 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
Let l be the larger and s be the smaller
then:
l-s=2
2l + 40 = 3s
(1) 2l - 2s = 4
(2) 2l -3s = -40
Substracting (2) from (1) we get
s = 44
from l-s = 2 we get l=46
2007-02-24 23:32:36 · answer #2 · answered by Amit Y 5 · 0⤊ 0⤋
2(x+2)+40=3x
2x+4+40=3x
x=44
so the nos are 44 and 46
2007-02-24 23:27:07 · answer #3 · answered by raj 7 · 0⤊ 0⤋
34.
2007-02-24 23:24:02 · answer #4 · answered by stunning_WARIS (jini 1 · 0⤊ 0⤋