Say an object is falling. Just how much does the speed at which it's falling effect the force of (C?

Question

impact when it hits the ground?

Answer 1

For a given ground hardness, the force is proportional to the rate of change of the object's speed with time since it first touches the ground. The falling terminal speed does not affect the force magnitude directly, but it gives more time for the impact force to exert.

Answer 2

If you mean the force due to air resistance, then experimentally this is proportional to the square of the instantaneous speed until this force exactly balances the weight of the object, After that , since the acceleration will be zero, the velocity will be constant and is called "terminal velocity"
Since you're talking about the force of impact then this is simply the rate of change of linear momentum of the object during the collision. The force will be larger if the object comes to rest in a shorter time. The change of momentum is m(vi - vf) where m = mass, vi and vf are the initial and final speeds(but vf =0) . If it takes a fraction (delta t ) of time to come to rest then the force of impact will be = mvi/(delta t). Therefore the answer to your question is that the impact force is proportional to the impact speed vi.

Answer 3

The acceleration of a falling merchandise is a continuing; it rather is many times 9.8 meters in line with 2d in line with 2d in the international. the fee of a falling merchandise, on the different hand, could be modeled with the aid of the equation f(x) = 9.8x + ok the place ok is the preliminary top of the object and x is the time in seconds. to come to a decision how briskly an merchandise is vacationing while it hits the floor, you're able to discover its preliminary top and the time while its top is 0 (at floor point). The latter could be got here upon with the aid of taking the antiderivative of the fee function it rather is 4.9x^2 + ok and placing it equivalent to 0.

Answer 4

Impact force is F=MA. not MG. (Mass * Acceleration, not Mass * Gravity)

MG is essentially the definition of weight.

The faster an object is falling, the larger the change in speed (acceleration) when it hits.

Impact force at 20 meters per second will be double the impact force of 10 meters per second. (same object and all other conditions the same)

Answer 5

first of all
we need to know what is the mass of the object let say the mass is m ( an unknown )
then the force or the impact on the ground should be , F=mg
where g is the gravitational field strength
in this case we need to assume that air resistance is neglected

Answer 6

Depends on the weight acting downwards.

F=kv^2

So,the larger the weight the larger the speed needed.