No, that is not correct.
It's x=0, z=0.
Compare it to the 2-dimensional situation: If a point is on the y axis, then x=0, and y can take any value at all.
In 3 dimensions, if the point is on the y axis, y can take any value at all. Picture the point as starting off at O, and moving to its current position. Only its y value has changed, x and z remain at 0.
Every equation stating or relating coordinates reduces the "degree of freedom", or "dimensions", by 1. With 3 coordinate axes, one linear equation reduces the 3-D space to a plane. To go down to a line (one dimension) we need two equations.
Thus 3x - 8y - 2z = 38 is the equation of a plane containing the points (4, -2, -5), (0, 1, -23), (10, -3, 8) and many more!!
2x - 4 = 15 - 3y = z - 1 are the equations defining a line through the points (2, 5, 1), (5, 3, 7), (-1, 7, -5) and many more.
2007-02-24 19:22:26
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answer #1
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answered by Hy 7
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you got it right
but you should write as the following:
0x+y+0z=D (not =y)
2007-02-25 03:17:50
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answer #2
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answered by abd 5
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