(a): Solve for the amount of force exerted on an 8-kg ball rolling at 2 m/s when it bumps into a pillow and stops in o.5 s
(b): How much force does the pillow exert on the ball?
2007-02-24 18:29:13 · 4 answers · asked by Nice Girl 1 in Science & Mathematics ➔ Physics
F = m x a
F = 8kg x 2m/sec / 0.5 sec
F = 32 kgm/(sec^2) =32 N
Part b:
32 N
2007-02-24 18:36:12 · answer #1 · answered by Hk 4 · 0⤊ 0⤋
a.
v=0,u=2m/s,t=0.5
v=u+at
0=2+0.5a
a=-4m/s^2
F=ma
=8x4
=32N
b.
Force exert on ball=32N
2007-02-25 08:33:56 · answer #2 · answered by yan 2 · 0⤊ 0⤋
F=rate of change of momentum=(8x2)/0.5=32N
2007-02-25 03:06:02 · answer #3 · answered by Anonymous · 0⤊ 0⤋
x=1/2(v+v0)t+x0--------->x=1/2(2)(0.5) + 0------>x=0.5 m
v^2 -v0^2 = 2ax------------>4 - 0=2(a)(0.5)--------->a=4 m/s^2
F=ma ----------->F=(8)(4)=32 ---------> f=32 N
2007-02-25 04:44:24 · answer #4 · answered by Anonymous · 0⤊ 0⤋