help!
2007-02-24 17:35:55 · 6 answers · asked by Allen 3 in Education & Reference ➔ Homework Help
2x^2 = 6x
Set the equation equal to zero and factor:
2x^2 - 6x = 0
2x (x - 3) = 0
Now, solve for x:
x - 3 = 0 ----> x = 3
2x = 0 ------> x = 0
No offense, but this is not college level mathematics.
(It's Algebra II.)
Good luck in your studies.
2007-02-24 17:44:01 · answer #1 · answered by Mitch 7 · 3⤊ 0⤋
The easiest way is to break down the equation.
2 * (x * x) = 6 * x
If you divide both sides by x (as long as you divide BOTH sides, you don't change the meaning of the equation), you get:
2 * x = 6
Divide both sides by 2, and you get...
x = 3
If, instead, the problem had been (2x)^2 = 6x, then there would have been an extra step or two, and the result wouldn't have been an integer, but the process would be the same.
2007-02-24 17:45:10 · answer #2 · answered by TravelDave 1 · 0⤊ 3⤋
2x^2-6x=0
2x(x-3)=0
x=0 and 3
subtract 6x from both sides. factor out 2x.
2007-02-24 17:44:03 · answer #3 · answered by BananaPancakes 2 · 2⤊ 0⤋
2x^2 = 6x
2x^2 - 6x = 0
2x(x-3) = 0
2x = 0, therefore x = 0
and:
x - 3 = 0
x = 3
SO, x = 0 and x = 3
2007-02-24 18:41:09 · answer #4 · answered by lexibabe2468 2 · 1⤊ 0⤋
(2x)(2x)=6x
4x squared=6x
*Subtract 6x from both sides.
*Set equal to 0.
*Simply by breaking it into groups and solve.
2007-02-24 17:44:42 · answer #5 · answered by miyshoe 4 · 0⤊ 3⤋
x=3
factor out an X first
you get 2x =6
next time do it yourself kid
2007-02-24 17:43:45 · answer #6 · answered by Anonymous · 0⤊ 5⤋