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Are the following lines parallel, perpendicular, or neither? L1 with equation x – 4y = 20 L2 with equation 4x + y = 4

2007-02-24 16:41:02 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

x - 4y = 20
4x + y = 4

One easy way of telling they're parallel, perpendicular, or neither is to put both lines in slope intercept form.

x - 4y = 20
-4y = -x + 20
y = (1/4)x - 5

4x + y = 4
y = -4x + 4

So we have

L1: y = (1/4)x - 5
L2: y = -4x + 4

The slopes are 1/4 and -4.
They're not parallel, because the slopes must be the same to be parallel.
They are, however, perpendicular, because their product is equal to (-1).

2007-02-24 16:45:51 · answer #1 · answered by Puggy 7 · 0 0

these lines are perpendicular to each other. the condition for two lines to be perpendicular is m1 * m2 = -1.
here,
L1: m1 = 1/4
L2: m2 = -4

2007-02-25 00:45:39 · answer #2 · answered by Anonymous · 0 0

find the slopes of the lines
x-4y=20
-4y=-x+20
y=1/4x-5
m=1/4

4x+y=4
y=-4x+4
m=-4

the slopes of the two equations are negative reciprocals so the lines are perpendicular

2007-02-25 00:46:39 · answer #3 · answered by Al3xa 2 · 0 0

the following lines are perpendicular...just punch it into your TI calculator...y=4x-4 and y=-(20-x)/4....

2007-02-25 00:51:19 · answer #4 · answered by sugar_softball1 1 · 0 0

they are perpendicular
L1 has slope 1/4
L2 has slope (-4)
they are negative reciprocals
they are perpendicular

try to graph the lines to have a visual reference of your lines.

still need help? contact. rycryc@yahoo.com

2007-02-25 00:49:37 · answer #5 · answered by Anonymous · 0 0

umm. Math makes my head hurt

2007-02-25 00:46:21 · answer #6 · answered by Purtee56 3 · 0 0

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