Solve......?

Question

Find the intercepts of the graph of the given equation....

y= ( (x^2+3x) / (3x+1)^2 )

Y-int=
X-int=

Answer 1

Look at the numerator and solve for it's zeros

x(x+3), so y is 0 when x=0,-3 yint=(-3,0); (0,0)

Next set x=0

setting x=0 we get y=0 because this graph passes throught the origin it's both an x and y intercept.