The pro shop at the Wildwood Country Club ordered two brands of golf balls. Lightning balls cost $2.10 each, and the Par One balls cost $1.00 each. The total cost of Lightning balls exceeded the total cost of the Par One balls by $660.00. If an equal number of each brand was ordered, how many dozen of each brand were ordered?
2007-02-24 15:47:37 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
50 dozen
Difference Lightning - Par 1 = $1.10
Total Difference Lighting - Par 1 = $660
SO
600 balls bought (660/1.1)
600/12 = 50 dozen
2007-02-24 15:52:17 · answer #1 · answered by Anonymous · 2⤊ 1⤋
50 dozens of each brand.
x = y because it's the same number of balls for both brands.
2.10x = 660 + 1.00x.
x = 600
600/12 (dozens) = 50
2007-02-24 15:53:46 · answer #2 · answered by F1reflyfan 4 · 1⤊ 1⤋
The equation can be formed as follows,
2.10 x=x+660
1.10x=660
x=600=50 dozens
2007-02-24 15:53:52 · answer #3 · answered by Yako 2 · 1⤊ 1⤋
50 dozen.
The difference in cost for each ball is $1.10 ($2.10 - $1.00).
$660.00 divided by $1.10 is 600. So 600 Lightning balls were ordered, which means 600 Par One balls were also ordered.
600 divided by 12 (one dozen) is 50. 50 dozen of each balls were ordered.
2007-02-24 15:49:50 · answer #4 · answered by marklemoore 6 · 0⤊ 5⤋
Assume that lightning balls is x and par one is y.
x=y........1
2.1x-y=660.......2
Put the value of x=y into 2
2.1y-y=660
1.1y=660
y=600
So, they ordered 600 balls for each of them. It would be 50 dozens of each brand.
I hope this helps.:)
2007-02-24 15:54:23 · answer #5 · answered by Juni Mccoy 3 · 1⤊ 1⤋