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plzzzzzzzzzz help me?

what potential different is appliced to two metal plates .5m apart if the electric field between them is 2.5 times 10 to the third n/c?

2007-02-24 15:38:52 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics

1 answers

E=V/d

2.5E3*.5=V=1.25E3 or 1,250 V

2007-02-24 16:12:21 · answer #1 · answered by Rob M 4 · 0⤊ 0⤋

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