I need some help figuring out how to find the LCM of rational expressions in terms of their denominators. i cant seem to find anything on the internet for it...thanks
2007-02-24 15:01:15 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
i dont have a problem, im just wondering how to do them step by step.
2007-02-24 15:07:20 · update #1
ok dear i will give you the easiest way in the world
multiply the two deonminators it is the lcm
(x/y)+(a/b)=(xb+ya)/yb
e.x ( 1 / 5 ) + ( 2 / 7 )= ( 1*7 + 2*5)/35 = 17/35
2007-02-24 15:31:06 · answer #1 · answered by emy 3 · 0⤊ 0⤋
You write the denominators in factored form and take one of each to the largest exponent.
Examples:
2(x+3) and (x+3)^2
LCM: 2(x+3)
2*5(x+3)^2 and 5(x+3)^3 and 2^2(x+3)
LCM: 2^2(5)(x+3)^3
3(x+3) and 7(x-3)
LCM: 3*7(x+3)(x-3)
2007-02-24 23:10:36 · answer #2 · answered by lizzie 3 · 0⤊ 0⤋
isn't it typically multiplying their denominators together, with cross-reduction if necessary?
2007-02-24 23:09:30 · answer #3 · answered by lifelesswonder 4 · 0⤊ 0⤋
What's the problem?
2007-02-24 23:05:47 · answer #4 · answered by Anonymous · 0⤊ 0⤋