i am not here to get answers to all of my homework questions. it is just some of them i do not understand so i come here to get a better understanding for the kind of math problems i post up here i have trouble with.
as i going to say.... what happens when you have the two same numbers with the same variables.
like this 3-3y=31-3y
i do not need the answers, all i need to know is how do i take off the two -3y's
2007-02-24 14:57:37 · 8 answers · asked by Anonymous in Education & Reference ➔ Homework Help
well here is the full problem
3-3(y-2)<13-3(y-6)
2007-02-24 17:39:39 · update #1
the eqaution is impossible. you will hvae to add 3y to both sides. when you do that, it will be 0. so...
2007-02-24 15:07:14 · answer #1 · answered by TJM 2 · 0⤊ 0⤋
add 3y to each side, 3y and 31...3y will cancel each other out, then you take 31plus 3 and divide it by 3
2007-02-24 23:07:06 · answer #2 · answered by kay 1 · 0⤊ 0⤋
well, normally you just add 3y from both sides
3 - 3y = 31 - 3y
8 - 3y + 3y = 31 - 3y + 3y
8 = 31
so this equation has no solution
2007-02-24 23:09:00 · answer #3 · answered by ... 3 · 0⤊ 1⤋
this equation is not possible from an algebraic stand point. souble check that you typed it correctly. generally whatever you do to one side of the equation you must do to the other, try to isolate the variable on one side to solve for its value
2007-02-25 01:40:12 · answer #4 · answered by rubbingbirds 2 · 0⤊ 0⤋
the answer would be 3=31 which is incorrect, maybe you typed the equation wrong.
2007-02-24 23:07:47 · answer #5 · answered by fre212eve . 2 · 0⤊ 0⤋
Add them algebraically on both sides
Never Mind....
2007-02-24 23:00:04 · answer #6 · answered by Daughter of a Coma Guy 7 · 0⤊ 0⤋
add "3y" to both sides
2007-02-24 23:00:02 · answer #7 · answered by ? 2 · 0⤊ 0⤋
this equation is impossible.
2007-02-24 23:00:39 · answer #8 · answered by Skater 2 · 0⤊ 0⤋