How many grams of NaOH are contained in 270.0 mL of a 0.550 M sodium hydroxide solution?

Answer 1

The first thing to do is to find out how many moles of NaOH is present in the solution. Using the fact that molarity is the number of mole of solute per liter of solvent, you can multiply the molarity(.550 mole/L) by the number of liters (.270 L) to find that there are .1485 moles of NaOH in the solution.
Ok, the next thing you neeed to do is find the molecular mass of NaOH, by adding the atomic masses of the Na, O, and H.

22.9898 g/mol (Na) + 15.994 g/mol (O) + 1.00794 g/mol (H) =
39.992 g/mol (NaOH.

Now that you know the molecular mass of NaOH and the amount of moles of NaOH, just multiply them to find the mass of NaOH present in the solution.

.1485 moles of NaOH * 39.992 g/mol NaOH = 5.939 g NaOH

Good luck with your future chemistry studying!

Answer 2

Approximately 5.94g