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I'm trying to solve this problem sec x = -5
I know you have to find the inverse sec of 5 which is 78.5
so you get for x 78.5 and 258.5 but how do you do it in the calculator
I know secant is 1/cos but what is sec^-1 in the calculator?

2007-02-24 13:34:27 · 10 answers · asked by alikat4392 4 in Science & Mathematics Mathematics

10 answers

You don't! Instead, switch the problem over to cosines and deal with it that way.

sec(x) = -5
1/cos(x) = -5
cos(x) = -1/5

Then use your inverse cosine function and interpret your solution accordingly!

2007-02-24 13:44:42 · answer #1 · answered by Anonymous · 3 0

Inverse Secant

2016-12-12 08:08:41 · answer #2 · answered by bebout 4 · 0 0

Find The Inverse Calculator

2016-10-01 05:32:58 · answer #3 · answered by youngman 4 · 0 0

This Site Might Help You.

RE:
How do you put the inverse secant into the calculator?
I'm trying to solve this problem sec x = -5
I know you have to find the inverse sec of 5 which is 78.5
so you get for x 78.5 and 258.5 but how do you do it in the calculator
I know secant is 1/cos but what is sec^-1 in the calculator?

2015-08-13 06:39:41 · answer #4 · answered by Anonymous · 0 0

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Switch the problem over to cosines and deal with it that way. Example: sec(x) = -5 1/cos(x) = -5 cos(x) = -1/5 Then use your inverse cosine function and interpret your solution accordingly.

2016-04-01 04:04:48 · answer #5 · answered by Anonymous · 0 0

On my TI-84 it is the following steps:

First, press the paratheses button "(", press cos button, enter your value by pushing the negative sign button(it's buttom right of the calculater next to the enter key), then enter 5, and then close the parathese ")". Push the x^-1 button which is on the far left side of the calculator which is below the math button and above the x^2 button. Finally close the parathese by pusshing the ")" button.

You should come up with (cos(-5)^-1) and press buttons. I think you're mode has to be in radians. You can set that by pressing the mode button next to your second button. hope that helps, sorry I couldn't explain it any clearer.

2007-02-24 13:44:59 · answer #6 · answered by ... 1 · 0 2

let asec(x)=f(x)

thus sec(f(x))=x. And since sec(f(x))=1/cos(f(x)), then

1/cos(f(x))=x

therefore f(x)=acos(1/x)=asec(x)

acos(1/x) may typed into a calculator using arc cos funkchin

2015-08-15 16:57:24 · answer #7 · answered by Have A Nice Day 1 · 0 0

It takes ten seconds for the YahooAnswers page to display for me to be able to click on the [add your answer] box. does this mean my computer is slow??

2016-08-23 19:16:29 · answer #8 · answered by Anonymous · 0 0

since you want the inverse (1/cos)^-1 = cos

2007-02-24 13:44:24 · answer #9 · answered by leo 6 · 0 2

But: sec(x) = 1/cos(x)

also, cosec(x) = 1/sin(x)

2007-02-24 13:53:47 · answer #10 · answered by modulo_function 7 · 0 1

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