how to sketch graph of y = x-1 / x+1?

Answer 1

asymptote at x = -1
when substistute a value slightly smaller than y = 0, you will get a large positive value of x
when substistute a value slightly larger than y = 0, you will get a large negative value of x
when substistute a value slightly smaller than x = -1, you will get a large positive value of y
when substistute a value slightly larger than x = -1, you will get a large negative value of y

Answer 2

This function has asymptotes at y = 1 and x =-1.
The graph starts at x = - infinity and very small values of +y and essentially hugs the x-axis until it gets close to x = -1 at which time it shoots upwards always getting closer to the line x = -1 but never quite getting there no matter how large y gets.

There is a discontinuity at x = -1 So the function resumes at large negative values of y, and hugs the y axis until it gets close to x = 0 where it crosses the y axis at y=-1, turns sharply right crosses the x-axis at x=1 and then continues to get closer and closer to the line y = 1 as x goes to + infinity.

Answer 3

It would be 2 curves, undefined at x = -1 starting close to the y axis in the neg direction, increasing as it approaches -1. On the other side of -1, it would start at (0,-1) and be abive the x axis in the positivedirection.

Answer 4

To draw the sketch of y = (x-1)/(x+1)...
ONe need to have an graph paper and then get the values of Y for differernt values of X startinf from -5 to +5 as per your requirement.
then take the poper scale on X-axis & on Y-axis and then plot the points and then join the points with smooth curve............

Answer 5

for a graph, go to http://www.calculator.com/calcs/GCalc.html

type in (x - 1)/(x + 1), click enter on the keyboard

Answer 6

there is an imaginary one infront of the x's put that over 1 which gives you your rise and run and -1 and +1 is your y-intercept