2007-02-24 12:35:15 · 8 answers · asked by Bob F 1 in Science & Mathematics ➔ Mathematics
sqrt(-192)/16 =
sqrt(64 * -3)/16 =
(8sqrt(-3))/16
sqrt(-3)/2
2007-02-24 13:00:39 · answer #1 · answered by Sherman81 6 · 0⤊ 0⤋
Because of sqrt-192/16 = -8\/3/16 = sqrt-3/2
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2007-02-24 21:01:49 · answer #2 · answered by aeiou 7 · 0⤊ 0⤋
You can't take the sq rt of a neg number without using i.
sqrt 192 = sqrt 64(sqrt3) = 8 sqrt 3 Divide by 16,
sqrt 3 / 2
2007-02-24 20:39:49 · answer #3 · answered by richardwptljc 6 · 0⤊ 0⤋
sqr( -192)/16 = sqrt ( -48) / 8 = sqrt ( -12) / 4 = sqrt (-3) / 2
2007-02-24 20:47:06 · answer #4 · answered by hustolemyname 6 · 0⤊ 0⤋
sqrt(-192)= sqrt(64*-3)=sqrt(64(sqrt(-3))= 8sqrt(-3)
So sqrt(-192) = 8sqrt(-3)/16 = sqrt(-3)/2
2007-02-24 20:43:59 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋
sqrt(-192) =sqrt(64)sqrt(-3)=8sqrt(-3)
so 8sqrt(-3)/16 =sqrt(-3)/2
2007-02-24 20:40:49 · answer #6 · answered by leo 6 · 0⤊ 0⤋
-196=16*12
Sqrt(196)=Sqrt (16) *Sqrt(12)
4*2*sqrt(-3)/16
=sqrt(-3)/2
just factor out
2007-02-24 20:42:19 · answer #7 · answered by locomexican89 3 · 0⤊ 0⤋
because sqrt from negative numbers don't exist. There's no number, positive or negative, that multiplied by it self can give you a negative number.
+ x + = +
- x - = +
2007-02-24 21:09:05 · answer #8 · answered by robertonereo 4 · 0⤊ 1⤋