English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Following the steps but i keep getting wrong answer..The question is What mass of Oxygen in grams can be prepared from 24.0g of H2O2? The answer I get is 22.58g O2 but the back of the book says 11.3g O2..Can someone tell me why I have double?

2007-02-24 11:03:28 · 6 answers · asked by Toothie 2 in Science & Mathematics Chemistry

6 answers

First, balance the chemical equation:

2 H2O2 = 2 H2O + O2

Next, figure out how many moles of peroxide (H2O2) you have:

24.0 g peroxide * ((1 mole peroxide) / (34.0 g peroxide)) = approx. 0.706 moles peroxide

Now, how many moles of oxygen can you get:

0.706 moles peroxide * ((1 mole oxygen molecule) / (2 mole peroxide) = 0.353 moles oxygen molecule

Now, the mass of oxygen:

0.353 moles oxygen molecule * ((32.0 g oxygen) / (1 mole oxygen molecule) = 11.3 g oxygen

I usually setup the above calculations as a chain of equations, looking like:

24.0 * (1 / 34.0) * (1 / 2) * (32.0 / 1) = 11.3

and include labels since they help me to remember what I'm looking to convert to next, and what number is in the numerator versus the denominator (labels should cancel).

2007-02-24 11:29:06 · answer #1 · answered by Dan 3 · 0 0

im not sure why you keep getting double the answer without actually seeing your workings, because it coulod be a number if things. i worked it out and got the right answer so heres how i done it. if u got any questions feel free to e-mail me.hope it helps.
2H2O2---> 2H2O + O2
Find the number of moles of H2O2: 24.0g/34.02g/mol = 0.705mol
ratio box the number of moles over to get the number of moles for O2: (0.705)(1)/2 = 0.352mol
then find the mass for O2 = (0.352mol)(32.00g/mol) = 11.3g

2007-02-24 11:15:28 · answer #2 · answered by Anonymous · 0 0

The balanced equation for this reaction is
2(H202) = 2(H2O) = O2
24 grams of H2O2 is .70 moles. Since the ratio of H2O2:O2 is 2:1 there is .35 moles of O2 produced.
o.35moles X 32 grams/mole = 11.2 grams of O2.

2007-02-24 11:54:34 · answer #3 · answered by John R 2 · 0 0

Molecular weight of H2O2 = 34 gram/mol, O2, 32 grams. so.
24grams H2O2 * 32 grams O2/(34 grams H2O2) I think your answer is correct.

2007-02-24 11:09:52 · answer #4 · answered by Anonymous · 0 0

It depends what reaction is occuring. If it's

H2O2 -> H2 +O2

then your answer is right, but the natural reaction is the following

2H2O2 -> 2H2O +O2

This reaction actually spontaneously happens all the time as it is a more favourable state to be in. If this is the reaction then you only liberate half the maximum amount of oxygen that you could get.

2007-02-24 11:18:14 · answer #5 · answered by Anonymous · 0 0

to discover quantity basically multiply lxwxh, you get 50m^3, multiply this via .2095 to get the quantity occupied via oxygen. Then convert the quantity to L, bear in mind 1cm^3=a million mL. Then replace into this equation, that's by-fabricated from appropriate gas equation: mols=PV/RT P=tension V=quantity R=proportionality consistent T=temperature kelvin at STP temp is 273 ok, tension is a million atm as quickly as you have the form of mols, multiply via the molar mass of oxygen to get mass.

2016-10-01 22:27:24 · answer #6 · answered by aubrette 4 · 0 0

fedest.com, questions and answers