A skier of mass 50.0 kg is pulled up a snow-covered slope at constant speed by a tow rope that is parallel to the ground. The ground slopes upward at a constant angle of 25 degrees above the horizontal and you can ignore friction.
What is the tension in the tow rope.
2007-02-24 10:38:54 · 2 answers · asked by keenpeach25 2 in Science & Mathematics ➔ Physics
The skier's weight acts vertically, but since (s)he is on an incline, part of the force is going into the ground and part of it acting down the slope. Draw it out, and you'll be able to see what I mean.
Since we are ignoring friction, the tension in the rope is going to be equal only to the portion of the weight that would pull the skier back down the slope, or 50*9.8*sin25, or 207.1N
2007-02-24 11:00:48 · answer #1 · answered by lango77 3 · 0⤊ 0⤋
T = 50 kg * 9,80 m/seg^2 * sin 25, now use your calculator.
2007-02-24 19:00:29 · answer #2 · answered by Anonymous · 0⤊ 0⤋