If f(x) = ln (cot e^x), then f '(x) =?

1 ⤊

If f(x) = ln (cot e^x), then f '(x) =?

If f(x) = ln (cot e^x), then f '(x) =?

possible solutions....

a. e^x(cot e^x)

b. -e^x(cot e^x)

c. e^x (sec e^x )(csc e^x)

d. -e^x (sec e^x )(csc e^x)

e. e^x(tan e^x)

f. - e^x(tan e^x)

g. none of these

2007-02-24 10:31:45 · 2 answers · asked by Olivia 4 in Science & Mathematics ➔ Mathematics

2 answers

Use the chain rule

y=f(g(x)

y'=f'(g(x))*g'(x)

f'(x)=1/(cot(e^x)*(-csc(e^x))^2*e^x
=-2*e^x*tan(e^x)*(csc(e^x))^2
=-e^x*sec(e^x)*csc(e^x) (D)

2007-02-24 10:41:50 · answer #1 · answered by Rob M 4 · 1⤊ 0⤋

DO YOUR OWN HOME WORK!

2007-02-24 10:34:22 · answer #2 · answered by Anonymous · 0⤊ 2⤋