Can anyone help with this calculus problem below....?

Question

(4/3)(3^1/2 )
∫ [1/(16 + x^2)] dx =
0

possible solutions....

a. π/24

b. π/12

c. π/6

d. 2π/9

e. π/4

f. π/3

g. π/2

h. π

i. none of these

Answer 1

Int = 1/16* Int 1/[1+(x/4)^2] = (1/16) *4 Arctan(x/4)=1/4Arctanx/4
At 0 it is 0 and at 4/3 3^1/2 It is 1/4 Arctan3^1/2 /3 which is=

=1/4*pi/6 = pi/24 (a)