Find two numbers whose sum is -1 and whose difference is 10?

Question

a) Find two numbers whose sum is -1 and whose difference is 10

b)Beer A is 6% alcohol and beer B is 2% alcohol. How many liters of each should be mixed in order to get 50L of a mixture that is 2.3% alcohol?

Answer 1

a) x+y = -1
x - y = 10

2x = 9

x = 9/2

x+y = -1

9/2 + y = -1

y = -11/2



.06x+.02y =50(0.23)

x + y = 50


x = 13 y = 37

Answer 2

permit A and B be the two numbers. If the sum is 10, then A+B=10. If their distinction is one million, then A-B=one million. you at the instant have 2 equations with 2 unknowns. sparkling up one equation for A, plug this fee into the 2nd equation and sparkling up that for B. Now placed the fee of B in the two equation to sparkling up for A. you will then have the values of the two A and B.

Answer 3

(x + y = -1)
+(x- y = 10)
----------------
x + x + y - y = -1 + 10
2x = 9
x = 4.5
y = -5.5


.06A + .02B = 50(.023) = 1.15
A + B = 50

Multiply (A + B = 50) by .02 and subtract it:
.06A + .02B = 1.15
-.02A - .02B = -.02(50)
-------------- -----------------
.04A + 0B = .15
A = 3.75
B = 50 - A = 46.25
3.75 L of A, 46.25 L of B

Answer 4

Question 1: 4.5 and -5.5
That's all I got now, bye bye

Answer 5

School home work is assigned to help you to learn.