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possible solutions....

a. 2e^2x cot e^2x

b. -2e^2x tan e^2x

c. 2e^2x (sec e^2x )(csc e^2x )

d. -2e^2x (sec e^2x )(csc e^2x )

e. -2e^2x cot e^2x

f. 2e^2x tan e^2x

g. none of these

2007-02-24 09:37:23 · 1 answers · asked by chris 2 in Science & Mathematics Mathematics

1 answers

A

2007-02-24 15:31:47 · answer #1 · answered by bruinfan 7 · 0 0

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