2007-02-24 09:08:34 · 7 answers · asked by matoro97116 1 in Science & Mathematics ➔ Mathematics
1, 5, 13, 29, 61, 125, 253
a(n) = a(n-1)*2 + 3
2007-02-24 09:13:11 · answer #1 · answered by kuxuru 3 · 1⤊ 2⤋
The pattern is 2x + 3 (multiply the term by 2 and add 3 each time...)
1*2 = 2, + 3 = 5. 5 * 2=10, + 3=13, etc...so.....
29*2 = 58, + 3 = 61
61*2 = 122, + 3 = 125
125*2 = 250, + 3 = 253
So the next 3 numbers are 61, 125, 253.
2007-02-24 09:12:33 · answer #2 · answered by Anonymous · 0⤊ 0⤋
1, 5, 13, 29, 61, 125, 189
the difference between 1 and 5 is 4, double that (8) and you have the difference between 13 and 5... double that (16) and you have the difference between 13 and 29.. keep doing that and you'll have the last three digits...
2007-02-24 09:16:23 · answer #3 · answered by danielle 2 · 0⤊ 0⤋
1,5, 13,29, 61, 125, 253
1+4=5, 5+8= 13, 13+16= 29, and so on.
Add 4 to start, then keep doubling
2007-02-24 09:15:09 · answer #4 · answered by jbean444 3 · 0⤊ 0⤋
1 + 2 squared =5
5 + 2 cubed=13
13 + 2 to the fourth= 29
29 + 2 to the fifth= 61
61 + 2 to the sixth= 125
125 + 2 to the 7th= 247!
2007-02-24 09:12:23 · answer #5 · answered by kiddo 4 · 1⤊ 0⤋
61, 125, 253
2007-02-24 09:22:32 · answer #6 · answered by Toeless_Joe_Jackson 5 · 0⤊ 0⤋
61,125,253
2007-02-24 09:13:17 · answer #7 · answered by kapmakunat 2 · 0⤊ 0⤋