possible book solutions....
a. 0
b. 0.16
c. 0.57
d. 1.44
e. 3.48
f. 4.49
g. 8.68
h. none of these
2007-02-24 09:06:18 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
integrate arcsin(x) over [0,1] to get PI/2-1 = 0.5707963268. The answer is c.
2007-02-24 09:09:34 · answer #1 · answered by kuxuru 3 · 0⤊ 0⤋
Integrate arcsin(x) on the interval [0,1].
â«arcsin(x) dx
Let
u = arcsin(x)
du = dx/â(1 - x²)
x = sinu
â(1 - x²) = cosu
du = dx/cosu
cosu du = dx
When
x = 0, u = arcsin(0) = 0
x = 1, u = arcsin(1) = Ï/2
â«arcsin(x) dx | [Evaluated on [0,1]
= â«{ucosu}du | [Evaluated on [0,Ï/2]
= usinu - cosu | [Evaluated on [0,Ï/2]
= [(Ï/2)*1 - 0] - [0*0 - 1]
= Ï/2 - 1 â 0.5707963
The answer is c. 0.57.
2007-02-24 17:40:10 · answer #2 · answered by Northstar 7 · 0⤊ 0⤋
c? if so i can explain
2007-02-24 17:15:31 · answer #3 · answered by Erin D 1 · 0⤊ 0⤋