the equation is this: 1 - (AK/P) = (1 + k)^-60
How can i solve for k?
2007-02-24 05:52:10 · 3 answers · asked by David M 2 in Science & Mathematics ➔ Mathematics
My apologies for not being clearer. The K on both sides of the equation are the same. I guess this drastically changes the responses that I've received.
2007-02-24 06:22:25 · update #1
Raising both sides to the sixtieth power will result in the left-hand side being (1+k)^-360...
You can take the natural log of both sides to get:
ln(1 - AK/P) = -60*ln(1 + k).
Divide by -60:
-1/60 * ln(1 - AK/P) = ln(1 + k).
This is equivalent to:
e^(-1/60 * ln(1 - AK/P)) = 1 + k.
so k = e^(-1/60 * ln(1 - AK/P)) - 1.
I hope you'll be able to simplify this ;)
2007-02-24 05:56:53 · answer #1 · answered by Bog-man 4 · 0⤊ 0⤋
Raise both sides to the 60th power and subtract 1 from the right side
2007-02-24 13:55:01 · answer #2 · answered by arbiter007 6 · 0⤊ 0⤋
raise to the -1/60...
(1 - (AK/P))^(-1/60) = (1 + k)
=> k= (1 - (AK/P))^(-1/60) - 1
2007-02-24 14:04:39 · answer #3 · answered by kuxuru 3 · 0⤊ 0⤋