Does anybody know how to do this? i am terrible at algebra and could really use your helpt to get my grade a little up. Thanks guys.
1. 16^n = 8^n+1
2. 2^2n= 1/16
3. sqrt(2^4x-6)= 4^x+2
4. 2^5x * 16^1-x= 4^x-3
I really appreciate your help. thank you guys.
2007-02-24 05:06:04 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I think number one is n=1/8
16^n=8^n+1
-8^n -8^n
8^n=1
\8 \8
n=1/8
2007-02-24 05:13:40 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Most of the time it's just rearrangement
16^n - 8^n = 1
8^n = 1
And which power always gives you the integer 1?
2^2n = 4^-2
2^2n = (2^2)^-2
Try this by yourself.
sqrt(2^4x -6) = 4^x + 2
2^4x -6 = (4^x + 2)^2
Easier now.
2^5x * (16-x) or is it (2^5x * 16) -1?
2007-02-24 05:15:14 · answer #2 · answered by Orange Peel 2 · 0⤊ 0⤋
1) 16^n = 2^4n
8^n+1 = 2^3(n+1)
2^4n = 2^3(n+1)
4n = 3n + 3 n = 3
2) 2^2n = 2^-4
2n = -4
n = -2
Others are done the same way.
2007-02-24 05:12:36 · answer #3 · answered by richardwptljc 6 · 0⤊ 0⤋
1. 2^n+1
that should help you get started
2007-02-24 05:14:11 · answer #4 · answered by Billy B 2 · 0⤊ 0⤋
one question one answer please
2007-02-24 05:09:13 · answer #5 · answered by sm bn 6 · 0⤊ 0⤋