how do u find the y intercept in a quadratic function, x intercept, axis of symmetry?

Answer 1

for y intercept, let y=0 and solve from there
exact opposite for x intercept (let x=0)
axis of symmetry find vertex, then something??????

hope this helps!

Answer 2

If you have an equation like y=3x+3, to find the y-intercept, you substitute the "x" with a zero (0). y=3(0)+3; y=0+3; y=3. The y-intercept is 3 for this equation. To find out the x-intercept, you replace "y" with zero (0). 0=3x+3, -3=3x, x= -1. I don't know about the axis of symmetry.

Good luck!

Answer 3

axis of symmetry,assuming that u talking about a regular parabolic FUNCTION(NB!)(form f(x)=ax^2+bx+c) it would be the equation x=value of x at turning point.that line "divides" the parabola into 2 sides that are "similar". for the equation f(x)=ax^2 +bx+c the axis of symmetry would be x=-b/2a.turning point is (-b/2a,f(-b/2a))---where tthe maximum or the minimun point of the function.btw,im sure if u still at school,the proofs of everything that i just wrote is/should be on your syllabus/notes.