how would u calculate the final temperature?

Question

A 295-g aluminum engine part at an initial temp. of 3.00 degrees celsius absorbs 85.0 KJ of heat.
(c of Al=0.900 J/g K)

Answer 1

3°C + 273 = 276 K

85,000 ÷ (295 x 0.900) = 320 K

320 - 273 = 47°C (Final temp)

Answer 2

You have Celsius and Kelvin in your question here. Convert them to the same unit

Initial Temp * (0.295*C of Al) + 85000J = Final Temp * (0.295*C of Al)

Then rearrange it to find Final Temp.

Answer 3

use the equation: q = m c (T2-T1)

You've got q, m, c and T1. Plug them in and calculate T2