What is X^2 + 6X =5?

Question

is it X= -3

Answer 1

This is a quadratic equation and you will get two solutions for x
x^2+6x=5
=> x^2+2.x,3+(3)^2=5+9 [adding 3^2 or 9 to both sides
=>(x+3)^2=14
=>x+3=+-sqrt14
=>x= -3+- sqrt14

Answer 2

Check
(-3)^2 +6(-3) = 5
9 - 18 = 5
Nope, x is not -3

Solve by method of completing the square.
x^2+6x-5 = 0 (to make it a square add 14 to both sides)
x^2+6x+9 = 14
(x+3)(x+3) = 14
x+3 = sqrt14
x = sqrt(14) - 3
x = .742

Answer 3

x² + 6x = 5
x² + 6x - 5 = 0

Using quadratic formula:

x = (-6 +- √6² - 4(1)(-5))/2(1)

x = (-6 +- √56)/2

x = (-6 +- 2√14)/2

Answers:

x = -3+√14 or x = -3-√14

Answer 4

X^2 + 6X = 5

Rearrangement the equation:

X^2 + 6X - 5 = 0

It cannot be factorize from here. So, a formulae must be used to find the root.

It's too complicated for me to type the formulae here. Try searching the internet for formulae for root of quadratic equation.

An alternative would be using "completing the square" method.

Answer 5

x^2+6x-5 = 0

Using quadratic formula, I got
x = (-6±√56)/2 = -3±√14

Answer 6

no i don't think -3 is the answer. use the quadratic formula factoring doesn't help. and
my steps are
1.) x ^2+ 6x-5= 0
2.) substitute in the quadratic formula
3.) my and answers are -1 and -5.

Answer 7

well u first subtract 5 frm both sides:
X^2+6=5
X^2+6-5=0
then you use the quadradic equation (i think that's how u spell it lol)
the quadradic equation is: X=-b+- square root of (b^2-4ac) all over 2a.
hopefully it helps you and you understand. :)

Answer 8

I don't think the equation you've given will have a simple integer answer. Rearrange it, and use the quadratic equation to determine the solutions.

Answer 9

no that does not work

x + 6x(square) = 5(square)

i think x = 5/7

but not sure

Answer 10

(X+3)²-9=5
X+3=+/-sqrt(14)
X=-3+/-sqrt(14)
so it's not 3