If k(x)= 2(6^3x), then k' (x)=????

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2007-02-24 04:09:43 · 5 answers · asked by dell10314 1 in Science & Mathematics ➔ Mathematics

36x^(3x-1)

2007-02-24 04:33:47 · answer #1 · answered by Anonymous · 0⤊ 0⤋

If k(x)= 2(6^3x), then k' (x)=?
=2* (6^3x)(ln 6)(3)=6(ln(6)(6^3x)
In general, if f(x)= a^u, then f'(x) = a^u ln a times du/dx

2007-02-24 12:24:52 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋

k(x)= 2[6^(3x)]
lnk(x) = ln2 + 3xln6
k'(x)/k(x) = 3ln6
k'(x) = 2[6^(3x)][3ln6] = 6^(3x+1)ln6

2007-02-24 12:19:44 · answer #3 · answered by sahsjing 7 · 0⤊ 0⤋

6*6^(3x)*ln(6)

2007-02-24 12:29:49 · answer #4 · answered by Malvi 2 · 0⤊ 0⤋

6*6^(3x)*ln(6)

2007-02-24 12:14:25 · answer #5 · answered by Anonymous · 0⤊ 0⤋