Car A uses tires for which the coefficient of static friction is 1.1 on a particular unbanked curve. The maximum speed at which the car can negotiate this curve is 20 m/s. Car B uses tires for which the coefficient of static friction is 0.95 on the same curve. What is the maximum speed at which car B can negotiate the curve?
2007-02-24 04:03:19 · 2 answers · asked by vntraderus88 1 in Science & Mathematics ➔ Physics
what tom said
2007-02-24 04:18:25 · answer #1 · answered by smokesha 3 · 3⤊ 3⤋
The force needed to make a turn = mv^2/r
The force of friction = mu x mg
To make the turn, these two forces need to equal each other, so
mv^2/r = mu x mg (mass cancels out)
v^2 /r = mu x g
Use the equation above to find the radius of the turn.
r = v^2 / (mu x g)
r = (20 m/s)^2 / (1.1 x 9.8 m/s^s) = 37.1 m
Use v^2 /r = mu x g again to find the v of the second car
v = sqroot(r x mu x g)
v = sqroot(37.1 m x .95 x 9.8 m/s^2)
v = 18.6 m/s
2007-02-24 04:09:01 · answer #2 · answered by Thomas G 3 · 9⤊ 0⤋