Help with 8th grade math problem please?

Question

A cube with 3-inch edges is made using 27 cubes with 1-inch edges. Nineteen of the smaller cubes are white and eight are black. If the eight black cubes are placed at the corners of the larger cube, what fraction area of the larger cube is white?


Choices....
A) 1/9
B) 1/4
C) 4/9
D) 5/9
E) 19/27

Answer 1

You know the area of the cube is 27 inches cubed by multiplying length/width/height or 3X3X3=27. There are 3 row of 9 smaller cubes inside the large one.
4 out of 9 in a row are black leaving 5out of 9 that are white.
Answer D-5/9

Answer 2

D

for 1 face with 9 cubes (each 1in^2), the 4 corners is black. therefore, the other 5 is white. Ans: 5/9

(it does matter whether it's 1 face for 4 faces. Ultimately, the fraction will remain the same)

Answer 3

5 faces of each 9 are black, times 6 faces in the whole cube

30/9 = 10/3 = 3 1/3

Answer 4

in a single face of the cube there are 4 balck n 5 white.....take one face as a square...so there are total
5*6=30...white's surface area
4*6=24...black's.and toal surface area of thwe cube =3*3*6=54.
so the ratio=30/54=5/9.

Answer 5

D - 5/9

Answer 6

d