a convex quadrilateral whose diagonals are mutually orthogonal
2007-02-24 03:45:03 · 5 answers · asked by ~*^.£M.^*~ 1 in Science & Mathematics ➔ Mathematics
and all the sides are different lengths
2007-02-24 03:54:48 · update #1
A convex quadrilateral is on where all of the internal angles are less than 180 degrees. e.g. a square.
Diagonals that are mutually orthogonal means that if you draw the lines between opposite corners, they are perpendicular. The shape being described is some kind of parallelogram like a square, rectangle or rhombus.
2007-02-24 03:52:23 · answer #1 · answered by davidbgreensmith 4 · 0⤊ 0⤋
its a 4 sided shape with its sides curved outwards in which the diagonals (lines between the opposing corners) intersect at right angles
2007-02-24 04:35:40 · answer #2 · answered by Malvi 2 · 1⤊ 0⤋
break it down into its parts
convex - curved outwards
quadrilateral - shape with 4 sides
diagonal - line between opposing corners
mutually - the same
orthagonal - intersect at right angles
so its a 4 sided shape with its sides curved outwards in which the diagonals (lines between the opposing corners) intersect at right angles
ie a "fat" square
2007-02-24 03:55:29 · answer #3 · answered by Kev P 3 · 1⤊ 0⤋
sorry that just gone right over my head good luck hope you get the answer
2007-02-24 03:48:30 · answer #4 · answered by Anonymous · 1⤊ 0⤋
Here's the website for your answer:
http://www.gvsu.edu/math/students/bst/CONVEXQUADRILATERALS.htm
2007-02-24 03:57:55 · answer #5 · answered by Anonymous · 1⤊ 0⤋