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(1)14x + 6y 42
(2)x – y 3
a. x = 1; y = 5
b. x = 2; y = 2
c. x = 2; y = 8
d. x = 2; y = 4
e. x = 3; y = 0.5

2007-02-24 01:32:57 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

(1)14x + 6y 42
(2)x – y 3

it's not an equation!

if you mean:

14x +6y =42
x - 3=y

Solution:

>> x= y+3
>>> Substitute in previous equation ..

14(y+3) + 6y =42

---> 14y + 42 + 6y = 42
-----> 20y = 0 .. means y = 0 & X=3

2007-02-24 01:42:05 · answer #1 · answered by Fanano 4 · 0 0

Howdy! :)

I sure hope you're doing well. :) As for the question:

We have:

(1) 14X + 6Y = 42 &
(2) X -- Y = 3

First, we multiply (2) by 6 (meaning we multiply both sides of equation # 2 by 6!). We get:

(3) 6X -- 6Y = 18

Now, we add (1) & (3):

(1) 14X + 6Y = 42
+ (3) 6X -- 6Y = 18
----------------------------
20X = 60

We divide both sides by 20. We get:

X = 3.

Now we substitute this into (2). We get:

3 -- Y = 3

Y = 0

I think perhaps you may have mis-typed the last possible solution option: e. X = 3; Y = 0.5, where you meant to type Y = 0. So e is the feasible point!

I sure hope that helped and is as clear as can be for you to understand the solution as easily as possible. :) Good luck, take very good care and have a great day & a great weekend too. :)

Cheers! :)

2007-02-24 09:51:06 · answer #2 · answered by Cogano 3 · 0 0

Is there something missing Steph?

2007-02-24 09:38:38 · answer #3 · answered by RWPOW 2 · 0 0

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