Find the remainder , when x^4 + 2X^3 - 3X^2+4X-5 is divided by x^3-x-2
a)12x
b)4x-1
c)-1
d)x-1
ANS: 4x-1
My Solution :
Here is my answer : 12x-1
Please look at the solution how i have made it ....do you think there is any mistake in my calculation ?
http://img91.imageshack.us/my.php?image=remzl3.jpg
the answer is not matching with the given options.
please suggest me whats wrong .
2007-02-24 00:40:38 · 4 answers · asked by sanko 1 in Science & Mathematics ➔ Mathematics
Are you saying
x^4 + 2X^3 - 3X^2 + 4X - 5 = (x^3-x-2) (X^2 + 3X +2) + (12X - 1)
If so, you're wrong :-/
(X^2 ...) (X^2...) ends up being X^5
2007-02-24 01:00:20 · answer #1 · answered by Régis 2 · 0⤊ 0⤋
Err, you seemed to be copying the problem incorrectly...
If you are trying to find the remainder when dividing x^4 + 2X^3 - 3X^2+4X-5 is divided by x^2-x-2, then you are correct. :) No mistake in your work, congratulations. ^_^
2007-02-24 09:05:02 · answer #2 · answered by ? Woc Viet ? 2 · 0⤊ 0⤋
Sorry .My results don´t match any
x^4+2x^3-3x^2+4x-5 = (x^3-x-2)*(x+2) +(-2x^2+8x-1)<=Remainder
2007-02-24 12:23:54 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋
what r the little triangle thingys?
2007-02-24 08:46:29 · answer #4 · answered by bluecheese465 2 · 0⤊ 0⤋