2007-02-23 09:57:14 · 4 answers · asked by blacksmith37 1 in Science & Mathematics ➔ Engineering
The Heat of combustion for propane is 2204kJ/mol
The molecular weight of propane is 44.09 g/mol
The density of propane is 0.505 grams/cm^3 at 70 degrees F and 112 psia. This density value is approximate since the natural state of propane is a vapor.
First
2204kJ/mol/44.09g/mol=50.0kJ/g
0.505g/cm^3*50.0kJ/g=25.2kJ/cm^3
Convert kJ/cm^3 to BTU/gal:
25.2kJ/cm^3*0.948BTU/kJ*3785cm^3/gal=~90570 BTU/gal
So the answer is 90570 BTU/gal
2007-02-23 12:49:03 · answer #1 · answered by Scott S 4 · 0⤊ 0⤋
A lot, butane and propane is rated at 1450 BTUs per cubic foot were as natural gas is rated at 1130 BTUs per cubic foot. Propane must be changed from a liquid to a gas to get this figure. You might try to contact the Railroad Commision, they control Propane and Butane.
2007-02-23 10:26:36 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Propanes BTU content can change as it may have varying quantity of butane in it.
I had looked this up a few years ago (1985) and had some notes in the back of my Refrigeration Textbook so heres what I have.
Propane:
2520 BTU/FT3 @ 60F
36.5 CUFT of gas per gallon liquid
8.59 CUFT of gas per pound
91500 BTU/Gal liquid
2007-02-23 11:33:43 · answer #3 · answered by MarkG 7 · 0⤊ 0⤋
My data is very close to Mark G. I have 91,600BTU/Gal.
2007-02-24 18:02:53 · answer #4 · answered by charley128 5 · 0⤊ 0⤋