I just received the headset that I purchased off ebay and i have NO idea how it works! It didn't comewith anyinstructions, so I figured I would try to find help on my own. It is a motorola H500. It came with a charger but thats it. I charged it last light, but I don't know how to make it work. The phone I am using is a motorola l7 slvr. If anybody knows how I am to make it work, PLEASE let me know. I am leaving for a 6 hour road trip today, and I wanted to be able to use it. Please help.
2007-02-23 04:01:33 · 3 answers · asked by monkeysgirl04 3 in Consumer Electronics ➔ Other - Electronics
Okay, so I figured out how to discover the connection, but now when I place a call, there is no sound in either the phone or the headset?!
2007-02-23 04:22:42 · update #1
Here is a link to a manual for your bluetooth headset...
http://www.motorola.com/mdirect/manuals/QG-H500_9494A56O.pdf
2007-02-23 06:11:05 · answer #1 · answered by gkk_72 7 · 0⤊ 0⤋
Bluetooth is person-friendly for cellular telephones and that they often comprise an ac wall charger or motor vehicle charging kit. despite the fact that in case you desire some thing on your computing gadget this is slightly diverse through fact your computing gadget first has to have a bluetooth adapter. you will ought to study including your computing gadget documentation to work out in case you have a bluetooth adapter put in. If no longer you are able to in simple terms then will you be waiting to apply a bluetooth headpiece including your computing gadget, in spite of what voice utility you employ. yet extra in particular to respond to your question, I charge my bluetooth headset with an ac charger besides as in my motor vehicle.
2016-10-16 08:03:10 · answer #2 · answered by juart 4 · 0⤊ 0⤋
when you turn on the headset the phone should reconize it is on
and then try calling you house phone(so you dont have to test it out on some one elce) and see if you turn up the volume on the actual headset ther should be a button
2007-02-23 04:37:09 · answer #3 · answered by xXnevetsx360Xx 2 · 0⤊ 0⤋