Ive been trying to solve this answer all day, I dont have the answer so I dont know if mine is correct or not. Could somebody try this problem as well so i can compare?
At t= t0(subzero), one side of the rectangle is 3 m long, and its length is increasing at a rate of 2m/sec. The other side has constant length of 5 m. What is the rate of change of the area of the rectangle?
2007-02-22 04:26:41 · 2 answers · asked by cooltee13 1 in Science & Mathematics ➔ Engineering
Let's check for a couple of seconds, how the changing side would change its value and how that would affect the area of the rectangle.
Second 0
3*5 = 15
Second 1
(3+2)*5 = 25
Second 2
(3+4)*5 = 35
Second 3
(3+6)*5 = 45
Second n
(3+(n*2))*5 = 15+10n
As you can see, the area of the rectangle is increasing 10m^2 at a time. So, the rate of change of the area is of 10m^2/second
2007-02-22 04:42:21 · answer #1 · answered by F B 3 · 0⤊ 0⤋
A=5*(3+2t)
A = 15 +10t
dA/dt = 10 m^2/sec
2007-02-22 06:23:08 · answer #2 · answered by bignose68 4 · 1⤊ 0⤋